lenagonzalez84
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Find the sum of the geometric series for which a = 160, r = 0.5, and n = 6.

Sagot :

[tex]\\ \sf\longmapsto S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

[tex]\\ \sf\longmapsto S_n=\dfrac{160(1-0.5^6)}{1-0.5}[/tex]

[tex]\\ \sf\longmapsto S_n=\dfrac{160(1-0.015625)}{0.5}[/tex]

[tex]\\ \sf\longmapsto S_n=\dfrac{160(0.984378)}{0.5}[/tex]

[tex]\\ \sf\longmapsto S_n=80(0.984378)[/tex]

[tex]\\ \sf\longmapsto S_n=78.75[/tex]

Hi1315

Answer:

[tex]s _6 = 315[/tex]

Step-by-step explanation:

Here,

a = First term

r ,= common ratio

Now let's use this formula to find the sum of the above geometric series

[tex]s _n = \frac{a(1 - {r}^{n} )}{(1 - r)} \\ \\ s _6 = \frac{160(1 - {0.5}^{6} )}{(1 - 0.5)} \\ \\ s _6 = \frac{160 (1 - 0.015625)}{0.5} \\ \\ s _6 = \frac{157.5}{0.5} \\ \\ s _6 = 315[/tex]

Hope this helps you.

Let me know if you have any other questions:-)

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.