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CONSTRUCT ARGUMENTS Consider three points, (3, 7), (−6, 1), and (9, p) on the same line. Find the value of p. Justify your argument.

Sagot :

Answer:

p=11

Step-by-step explanation:

let A(3,7),B(-6,1),C(9,p) be the points.

or

B(-6,1),A(3,7),C(9,p) are the points in the same line.

let A divides BCin the ratio k:1

[tex]3=\frac{9k+1(-6)}{k+1} \\3k+3=9k-6\\3k-9k=-6-3\\-6k=-9\\k=\frac{-9}{-6} =\frac{3}{2} \\so~ratio~is~\frac{3}{2} :1\\or\\3:2\\again\\7=\frac{3p+2(1)}{3+2} \\5*7=3p+2\\3p=35-2=33\\p=\frac{33}{3} =11[/tex]

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