Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Given : A car starts from rest and accelerates at a constant rate. After the car has gone 50 m it has a speed of 21m/s. What is the acceleration of the car?
Solution : As per the question, initial velocity is 0 m/s and final velocity is 21 m/s. Distance travelled is 50 m and we need to get the acceleration of the car.
We need to use the third equation of motion. Second equation is invalid as time is given in the formula but as per the data third equation is more comfortable.
★ 3ʳᵈ eq. of motion : v² - u² = 2aS ★
Putting all the given values according to the formula we get
- (21)² - (0)² = 2a(50)
- 441 - 0 = 100a
- 441 = 100a
- a = 4.41
Henceforth, acceleration is 4.41 m/s²
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.