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A rectangle has perimeter 110 cm and its length is 1 cm more than twice its width.
Find the dimensions of a rectangle given that its perimeter is 110 cm and its length is 1 cm more than
twice its width.
Set up your solution using the variables L for the length, W for the width, and P for the perimeter.

Sagot :

mscalculator1

Answer:

37cm

Step-by-step explanation:

width = w

length = 2w+1

 

perimeter = 2(length +width)

 

110 =2(2w+1+w)

110 = 2(3w+1)

110 = 6w+2

108 =6w

18 = w

 

width = w = 18cm

length = 2w+1 =2(18)+1 =36+1 =37cm

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