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Sagot :
First we need to solve this
The first step is to multiply everything by its power
(5x^3y^2)^
So 5 is to put to the power of 3 that is 125
X ^2 has a power already to transfer powers we multiply
So x^3 x 3 = x^9
Because we don’t know x we can’t simplify x^6 so it stays this way
Next is y^2 x 3 so it is y^6
All together the new equation is 125 x^9 y^6
Now we do the same to the bottom half of this equation
4 z^5
4 doesn’t have a variable so it is powered not multiplied
4 to the 3 power is 64
Z^5 power turns in to z^15
The new equation is 64 z^15
The new problem becomes
125 x^9 y^6
———————
64 z^15
This would be the simplest form
The first step is to multiply everything by its power
(5x^3y^2)^
So 5 is to put to the power of 3 that is 125
X ^2 has a power already to transfer powers we multiply
So x^3 x 3 = x^9
Because we don’t know x we can’t simplify x^6 so it stays this way
Next is y^2 x 3 so it is y^6
All together the new equation is 125 x^9 y^6
Now we do the same to the bottom half of this equation
4 z^5
4 doesn’t have a variable so it is powered not multiplied
4 to the 3 power is 64
Z^5 power turns in to z^15
The new equation is 64 z^15
The new problem becomes
125 x^9 y^6
———————
64 z^15
This would be the simplest form
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