Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
First we need to solve this
The first step is to multiply everything by its power
(5x^3y^2)^
So 5 is to put to the power of 3 that is 125
X ^2 has a power already to transfer powers we multiply
So x^3 x 3 = x^9
Because we don’t know x we can’t simplify x^6 so it stays this way
Next is y^2 x 3 so it is y^6
All together the new equation is 125 x^9 y^6
Now we do the same to the bottom half of this equation
4 z^5
4 doesn’t have a variable so it is powered not multiplied
4 to the 3 power is 64
Z^5 power turns in to z^15
The new equation is 64 z^15
The new problem becomes
125 x^9 y^6
———————
64 z^15
This would be the simplest form
The first step is to multiply everything by its power
(5x^3y^2)^
So 5 is to put to the power of 3 that is 125
X ^2 has a power already to transfer powers we multiply
So x^3 x 3 = x^9
Because we don’t know x we can’t simplify x^6 so it stays this way
Next is y^2 x 3 so it is y^6
All together the new equation is 125 x^9 y^6
Now we do the same to the bottom half of this equation
4 z^5
4 doesn’t have a variable so it is powered not multiplied
4 to the 3 power is 64
Z^5 power turns in to z^15
The new equation is 64 z^15
The new problem becomes
125 x^9 y^6
———————
64 z^15
This would be the simplest form
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.