At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
First we need to solve this
The first step is to multiply everything by its power
(5x^3y^2)^
So 5 is to put to the power of 3 that is 125
X ^2 has a power already to transfer powers we multiply
So x^3 x 3 = x^9
Because we don’t know x we can’t simplify x^6 so it stays this way
Next is y^2 x 3 so it is y^6
All together the new equation is 125 x^9 y^6
Now we do the same to the bottom half of this equation
4 z^5
4 doesn’t have a variable so it is powered not multiplied
4 to the 3 power is 64
Z^5 power turns in to z^15
The new equation is 64 z^15
The new problem becomes
125 x^9 y^6
———————
64 z^15
This would be the simplest form
The first step is to multiply everything by its power
(5x^3y^2)^
So 5 is to put to the power of 3 that is 125
X ^2 has a power already to transfer powers we multiply
So x^3 x 3 = x^9
Because we don’t know x we can’t simplify x^6 so it stays this way
Next is y^2 x 3 so it is y^6
All together the new equation is 125 x^9 y^6
Now we do the same to the bottom half of this equation
4 z^5
4 doesn’t have a variable so it is powered not multiplied
4 to the 3 power is 64
Z^5 power turns in to z^15
The new equation is 64 z^15
The new problem becomes
125 x^9 y^6
———————
64 z^15
This would be the simplest form
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.