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Sagot :
Answer:
Step-by-step explanation:
x = 1 - i sqrt(2) ^ y = 10 + i sqrt(2)
x = 1 + i sqrt(2) ^ y = 10 - i sqrt(2)
Answer:
Step-by-step explanation:
y = 11 - x ----------(I)
y = 2x² - 4x + 6 -----------(II)
Substitute y = 11- x in (II)
11 - x = 2x² - 4x + 6
0 = 2x² - 4x + x + 6 - 11
0 = 2x² - 3x - 5
2x² - 3x - 5 = 0
Sum = -3
Product = -10
Factors = -5 , 2
2x² - 5x + 2x - 5 = 0
x(2x - 5) + (2x - 5) = 0
(2x -5 )(x +1)=0
2x - 5 = 0 ; x + 1 = 0
2x = 5 ; x = -1
x = 5/2
When x = -1 ; y = 11 - (-1) = 11 + 1 = 12
[tex]When x = \dfrac{5}{2} ; y = 11- \dfrac{5}{2}= \dfrac{22}{2}- \dfrac{5}{2}= \dfrac{17}{2}[/tex]
Solution: (-1 , 12) and (5/2 , 17/2)
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