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A penny is dropped from the Statue of Liberty

a. what is the velocity of the penny after 0.30 seconds

b. How far did the penny drop after 0.30 seconds


Sagot :

Answer:

a) The velocity is 2.94m/s

b) 0.441

Explanation:

a) Assume gravity is 9.8m/s^2

Use the equation below to solve for the velocity at 0.30 seconds

[tex]vf=vi+at[/tex],

vf =unknown velocity  vi= initial velocity vi=0m/s  a= 9.8m/s^2 t=0.30seconds

Step 1: Substitute the variables with the knowns

[tex]vf=0m/s+(9.8m/s^2)*0.30seconds[/tex]

Step 2: Solve

[tex]vf=2.94m/s[/tex]

b)

Use the equation below to solve for the displacement at 0.30 seconds

[tex]x=vit+\frac{1}{2} at^{2}[/tex]

Step 1: Substitute the same variables with the knowns

[tex]x=\frac{1}{2}*(9.8m/s^2)*(0.30seconds)^{2}[/tex]

Note that vi*t=0 as vi=0m/s

Step 2: Solve

x=0.441m