Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Solve by completing the square x^2-6x-4=0

Sagot :

Answer:

x = 3 ± [tex]\sqrt{13}[/tex]

Step-by-step explanation:

x² - 6x - 4 = 0 ( add 4 to both sides )

x² - 6x = 4

To complete the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(- 3)x + 9 = 4 + 9

(x - 3)² = 13 ( take square root of both sides )

x - 3 = ± [tex]\sqrt{13}[/tex] ( add 3 to both sides )

x = 3 ± [tex]\sqrt{13}[/tex]

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.