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write the solution in interval notation: 1/4x−3≥−1 and −3(x−2)≥2

Sagot :

armanarnav

Answer:Mark me as Brainliest please

Step-by-step explanation:

Let's solve your inequality step-by-step.

[tex]\frac{1}{4}x-3\geq -1[/tex]

Step 1: Add 3 to both sides.

[tex]\frac{1}{4} x-3+3\geq -1+3[/tex]

[tex]\frac{1}{4} x\geq 2[/tex]

Step 2: Multiply both sides by 4.

[tex]4*(\frac{1}{4} x)\geq (4)*(2)[/tex]

Answer:

x≥8

Let's solve your inequality step-by-step.

−3(x−2)≥2

Step 1: Simplify both sides of the inequality.

−3x+6≥2

Step 2: Subtract 6 from both sides.

−3x+6−6≥2−6

−3x≥−4

Step 3: Divide both sides by -3.

[tex]\frac{-3x}{-3} \geq \frac{-4}{-3}[/tex]

Answer:

=[tex]x\leq \frac{4}{3}[/tex]

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