nevillegirls4
Answered

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Find an equation of a line perpendicular to the given line and contains the given point. Write the equation in slope-intercept form.

y = ?

Find An Equation Of A Line Perpendicular To The Given Line And Contains The Given Point Write The Equation In Slopeintercept Form Y class=

Sagot :

maniknandini

Answer:

y = -1/5 x -2

Step-by-step explanation:

Given line y = 5x - 1

as in slope intercept form m = 5

point (5, -3)

for two lines to be perpendicular product of slopes must be -1\

so for new line  slope is

m1 * m2 = -1

5 * m2 = -1

m2 = -1/5

line equation is y - (-3) = -1/5 (x - 5)

y + 3 = -1/5 x + 1

y = -1/5 x + 1 - 3

y = -1/5 x -2

xenia168

Answer:

Step-by-step explanation:

Slope of the ⊥ line is ( - [tex]\frac{1}{5}[/tex] )

y - ( - 3 ) = - [tex]\frac{1}{5}[/tex] ( x - 5 )

y + 3 = - [tex]\frac{1}{5}[/tex] x + 1

y = - [tex]\frac{1}{5}[/tex] x - 2

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