Answered

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = –16x2 + 119x + 57

Sagot :

Answer:

7.89 seconds

Step-by-step explanation:

using the quadratic formula (-b+-√(b^2-4ac))/2a

a=-16 b=119 c=57

x=-0.451

and

x=7.889

time cant be negative so use the positive x

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