Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Two 2.5 kg bowling balls are 0.50 m apart. What is the force of gravity of the first bowling ball due to the
second? Compare this to the force of gravity on the second bowling ball due to the first.


Two 25 Kg Bowling Balls Are 050 M Apart What Is The Force Of Gravity Of The First Bowling Ball Due To The Second Compare This To The Force Of Gravity On The Sec class=

Sagot :

Answer:The answer is A

Explanation:

To determine the force, we use the equation

Fg= G m1 m2/r2

, where Fg is the force of gravity, G is the gravitational constant,

m1

is the mass of the first body,

m2

is the mass of the second body, and r is the radius. Hence, we have

Fg=6.67×10−11 N×m2/kg2×2.5 kg×2.5 kg/(0.50 m)2=1.7×10−9N

. Since this is a gravitational problem, the force on one body has the same force as the other body, but the directions are opposite.

Answer:

The answer is A have a good day!

Explanation:

View image miahannahperez
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.