Answer:
Coordinate of B: (3, -5)
Coordinate of C: (3, 5)
Coordinate of D: (0, -1)
Step-by-step explanation:
Point A is (-2, -5).
The distance between line AB is 5 units.
The distance between line BC is 10 units.
To find the point for B, the distance is 5 units on the x axis.
The x point for point B is -2 + 5 which is 3 units. x = 3
The y point doesn't change, so the coordinate of point B is (3, -5).
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The distance between line BC is 10 units.
To find the point of C, the distance is 10 unites on the y axis.
The y point for point b is -5 + 10 which is 5 units. y = 5
The x point doesn't change, so the coordinate of point C is (3, 5).
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We find an equation for line AC. The equation is y = mx + b.
Y is any y point on the line. X is any x point on the line. M is the slope of the line. B is the y-intercept of the line.
Since D is right on the y axis, this means that the x point of D is 0.
Point C is (3, 5) and point A is (-2, -5).
We use (y2 - y1) / (x2 - x1) and substitute. Y is the y point and x is the x point.
(5 - (-5)) / (3 - (-2)) = 10 / 5 = 2
The slope of the line is 2.
With this, we get the equation of y = 2x + b
We insert one of the random x point and y point which (in this case) I choose (3, 5).
Substituting, we get -
5 = 2 * 3 + b
5 = 6 + b
b = 5 - 6
b = -1
So the y-intercept of the graph is -1 and for the graph, we get -
y = 2x - 1
D is already the line of the y-intercept, but we can make sure by inserting the x point as 0.
y = 2 * 0 - 1
y = 0 - 1
y = -1
The coordinate of point D is (0, -1).