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A car of mass 600kg is moving at 15m/s. The driver accelerate gently to a final velocity of 30m/s so that a force of force acts on the car for 10s. Calculate the magnitude of the force that acting on the car during the 10s time interval.

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Answer:

F = 900 N

Explanation:

m = 600 kg

vo = 15 m/s

vt = 30m/s

t = 10 s

F = ?

vt = vo + at

30 = 15 + a (10)

15 = 10a

a = 15/10 = 1.5 m/s²

F = m. a

F = 600 . 1.5

F = 900 N