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Given 2m−65m−15, find the values of the expression in order if m={0,1,2,3}.

Sagot :

Answer:

If m=0,

2m-65m-15=0-0-15

                  =-15

If m=1,

2m-65m-15=2-65-15

                  =-78

If m=2,

2m-65m-15=4-130-15

                  =-141

If m=3,

2m-65m-15=6-195-15

                  =-204

2m-65m-15

m=0

2(0)-65(0)-15

= -15

2m-65m-15

m= 1

2(1)-65(1)-15

= 2-65-15

= 2-80

= -78

2m-65m-15

m= 2

2(2)-65(2)-15

= 4-130-15

= 4-145

= -141

2m-65m-15

m= 3

2(3)-65(3)-15

= 6-195-15

= 6-210

= -204

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