Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Answer:
x=403/24,3 = 16.58 gm MgO
EXPLANATION
The student burns 10 g of magnesium in air to produce magnesium oxide (MgO)
2Mg + 0 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.
Oxygen exist in nature as O2, diatomic.
so
The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).
2Mg + 02 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.
2 moles of Mg produce 2 moles of MgO
1 mole of Mg weighs 24.3 and produces 1 mole of MgO
Mg HAS AN ATOMIC MASS OF 24.3
Mg HAS A MOLAR MASS OF 24.3 +16 = 40.3gm/mole
so 24.3 gm of Mg produce 40.3 gm MgO
set up the ratio
10 gm Mg/x of MgO = 24.3/40.3
or
10/x = 24.3/40.3
cross multiply and isolate x (use Algebra I)
24.3x =403
x=403/24,3 = 16.58 gm MgO
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.