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The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).
2Mg + 0 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.


Sagot :

Answer:

x=403/24,3 = 16.58 gm MgO

EXPLANATION

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO)

2Mg + 0 + 2MgO

Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

Oxygen exist in nature as O2, diatomic.

so

The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).

2Mg + 02 + 2MgO

Calculate the maximum mass of magnesium oxide that could be produced in the reaction.

2 moles of Mg produce 2 moles of MgO

1 mole of Mg weighs 24.3 and produces 1 mole of MgO

Mg HAS AN ATOMIC MASS OF 24.3

Mg HAS A MOLAR MASS OF 24.3 +16 = 40.3gm/mole

so 24.3 gm of Mg produce 40.3 gm MgO

set up the ratio

10 gm Mg/x of MgO  = 24.3/40.3

or

10/x = 24.3/40.3

cross multiply and isolate x (use Algebra I)

24.3x =403

x=403/24,3 = 16.58 gm MgO