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Sagot :
Answer:
x=403/24,3 = 16.58 gm MgO
EXPLANATION
The student burns 10 g of magnesium in air to produce magnesium oxide (MgO)
2Mg + 0 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.
Oxygen exist in nature as O2, diatomic.
so
The student burns 10 g of magnesium in air to produce magnesium oxide (MgO).
2Mg + 02 + 2MgO
Calculate the maximum mass of magnesium oxide that could be produced in the reaction.
2 moles of Mg produce 2 moles of MgO
1 mole of Mg weighs 24.3 and produces 1 mole of MgO
Mg HAS AN ATOMIC MASS OF 24.3
Mg HAS A MOLAR MASS OF 24.3 +16 = 40.3gm/mole
so 24.3 gm of Mg produce 40.3 gm MgO
set up the ratio
10 gm Mg/x of MgO = 24.3/40.3
or
10/x = 24.3/40.3
cross multiply and isolate x (use Algebra I)
24.3x =403
x=403/24,3 = 16.58 gm MgO
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