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Sagot :
Answer:
a=6
b= -15
Step-by-step explanation:
third term --> n=3
a(3)^2 + b(3) =9
9a+3b=9
3(3a +b)=9
3a +b=9/3=3
3a + b=3 ------eqn1
sixth term n=6
a(6)^2 +6b =126
36a +6b=126
6(6a+b)=126
6a + b =126/6=21
6a + b=21----------eqn 2
eqn2 - eqn 1
(6a-3a) +(b-b) =21-3
3a=18
a=18/3=6
sub a= 6 into eqn2
6(6)+b=21
36 +b =21
b=21-36= -15
Answer:
a = 6 , b = - 15
Step-by-step explanation:
Substitute n = 3 and n = 6 into the nth term formula
a(3)² + 3b = 9 , that is
9a + 3b = 9 ( divide through by 3 )
3a + b = 3 → (1)
--------------------
a(6)² + 6b = 126 , that is
36a + 6b = 126 ( divide through by 6 )
6a + b = 21 → (2)
Subtract (1) from (2) term by term to eliminate b
3a + 0 = 18
3a = 18 ( divide both sides by 3 )
a = 6
Substitute a = 6 into (1) and solve for b
3(6) + b = 3
18 + b = 3 ( subtract 18 from both sides )
b = - 15
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