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Sagot :
Answer:
7
Step-by-step explanation:
[tex]a^{m}*a^{n}=a^{m+n}\\\\\\\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{7^{8}*7^{3}*7^{4}}{7^{9}*7^{5}}=\dfrac{7^{8+3+4}}{7^{9+5}}\\\\=\dfrac{7^{15}}{7^{14}}\\\\\\=7^{15-14}=7^{1}\\\\= 7[/tex]
Answer:
7^1
Step-by-step explanation:
since all the bases are same, we're going to use the law (a^m × a^n = a^m+n)
8+3+4= 15, hence, it's 7^15
we'll apply the same law for the denominator, 9+5= 14, so we'll get 7^15 ÷ 7^14
next we're gonna use the law (a^m ÷ a^n = a^m-n where m>n)
15-14 = 1
so our final answer is 7^1
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