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(w-x)^2 + 26x; if w = 6 and x = -1

Sagot :

Answer:

[tex]\boxed{\boxed{\sf 23}}[/tex]

Step-by-step explanation:

[tex]\boxed{\sf Hi\: there!}[/tex]

[tex]\sf (w-x)^2 + 26x[/tex]

[tex]\sf w=6[/tex]

[tex]\sf x=-1[/tex]

_____________________

→ [tex]\sf \left(6-\left(-1\right)\right)^2+26\left(-1\right)[/tex]

→ [tex]\sf 23[/tex]

»»————-　➴　————-««

Answer:

23

Step-by-step explanation:

w = 6

x = - 1

( w - x )^2

= ( 6 - ( - 1 ) )^2

= ( 6 + 1 )^2

= 7^2

= 7 * 7

= 49

26x

= 26 * - 1

= - 26

( w - x )^2 + 26x

= 49 + ( - 26 )

= 49 - 26

= 23

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