The polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=−3.
Find a possible formula for P(x). P(x)=,

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07-11-2021
Mathematics

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The polynomial of degree 5, P(x), has leading coefficient 1, has roots of multiplicity 2 at x=1 and x=0, and a root of multiplicity 1 at x=−3.
Find a possible formula for P(x). P(x)=,

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okiwix okiwix · Answer 1 · 2021-11-07T11:44:19-05:00

okiwix okiwix

07-11-2021

Sine the roots x=1 and x=0 have a multiplicity of 2, we know p(x)= (x-1)^2 (x)^2 (x-a). Since we also know x=-3 is a root, we have p(x)= (x-1)^2 x^2 (x+3)

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