A particle, initially 15 m from the origin and travelling at -2 ms), accelerates at a constant rate and ends up -20 m from the origin and travelling at -5 ms?

What is its acceleration?

Question

07-11-2021
Mathematics

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A particle, initially 15 m from the origin and travelling at -2 ms), accelerates at a constant rate and ends up -20 m from the origin and travelling at -5 ms?

What is its acceleration?

Sagot :

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Аноним Аноним · Answer 1 · 2021-11-07T11:48:43-05:00

the general equation for velocity in terms of acceleration and displacement is: v² = v₀² + 2ax.

Solve for a: a = (v² - v₀²)/(2x).

You are given v₀ and v, and x is easy to calculate since you are given its initial and final values. The rest is just arithmetic.

(note also: SI expressions have a required space between the coefficient and the unit symbol. Thus you should have things such as “15 m” and “-2 m·sˉ¹” instead of “15m” and “-2m·sˉ¹”.)

Sagot :

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