ib24rahim
Answered

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write the complex number 3+√-9 in standard form​

Sagot :

devishri1977

Answer:

3 + 3i

Step-by-step explanation:

[tex]i^{2} = -1\\\\3 + \sqrt{-9} = 3 +\sqrt{3*3*i^{2}}\\\\\\ = 3 +3i[/tex]

lovetthannah9

Answer:

3+3i

Step-by-step explanation:

3+[tex]\sqrt{-9\\}[/tex]

move 3 to the other side and add a value

[tex]\sqrt{-9}[/tex] = 3i

Then you take the square root of -9 which is 3

and there is nothing you can do to the other side so it stays 3i

so 3 + 3i is your answer

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