Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Ask your questions and receive precise answers from experienced professionals across different disciplines. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

i need help on this geometry problem please

I Need Help On This Geometry Problem Please class=

Sagot :

Answer:

60[tex]\sqrt{2}[/tex]

Step-by-step explanation:

sin x = opposite side / hypotenuse

sin 45 = 60 / y

y = 60 / sin 45 =60 / (1 / sqrt(2))

= 60 [tex]\sqrt{2}[/tex]

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.