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Sagot :
Answer:
see explanation
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]
(a)
[tex]\sqrt{3}[/tex] × [tex]\sqrt{6}[/tex]
= [tex]\sqrt{3(6)}[/tex]
= [tex]\sqrt{18}[/tex]
= [tex]\sqrt{9(2)}[/tex]
= [tex]\sqrt{9}[/tex] × [tex]\sqrt{2}[/tex]
= 3[tex]\sqrt{2}[/tex]
(b)
[tex]\sqrt{8}[/tex] × [tex]\sqrt{18}[/tex]
= [tex]\sqrt{8(18)}[/tex]
= [tex]\sqrt{144}[/tex]
= 12
>> Answer
_________
- Number (A.)
[tex] \sqrt{3} \times \sqrt{6} = ...[/tex]
[tex] = \sqrt{3 \times 6} [/tex]
[tex] = \sqrt{18} [/tex]
[tex] = \sqrt{9} \sqrt{2} [/tex]
[tex] = \bold{3 \sqrt{2}} [/tex]
.
- Number (B.)
[tex] \sqrt{8} \times \sqrt{18} = ...[/tex]
[tex] = \sqrt{8 \times 18} [/tex]
[tex] = \sqrt{144} = \bold{12}[/tex]
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