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Chemistry help!
How much 1.50 M H3PO4, in mL, would you need to add to 50.00 mL of 3.50 M Ca(OH)2 in order to neutralize the solution?

_____ of mL of H3PO4

Sagot :

zyanabanana01

Answer:

I think around 77

Explanation:

hold on let me look more into it

nutanraj654

Given 0.10M NaOH (0.10mol/lit NaOH)

0.2M H3PO4 ( 0.2 mol/lit H3PO4)

15 ml of H3PO4 or 0.015 lit of H3PO4

Find the volume of NaOH needed to neutralize the solution

Relate moles of H3PO4 with the moles of NaOH with the help of coefficients in front of NaOH and H3PO4 seen in balanced equations.

moles ↔ Litre use the definition of molarity (moles/liters)

Start with what is given for H3PO4

0.015 lit of H3PO4 x 0.2 moles of H3PO4 / lit of H3PO4 x 3 moles of NaOH/1 mole of H3PO4 x lit of NaOH/0.1 mol of NaOH = 0.09 lit or 90 ml.

What does the word neutralize mean?

Definition of neutralizing

transitive verb. 1: to make it chemically neutral. 2a: to counteract the activity or effect of making ineffective propaganda that is difficult to neutralize. b: kill, destroy.

Learn more about neutralizing at

https://brainly.com/question/23008798

#SPJ2

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