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Sagot :
Answer:
[tex] \sum_{n = 0}^{6} 4 + 6n \\ n = 0 \rightarrow4\\ n = 1 \rightarrow10 \\ n = 2 \rightarrow16 \\ n = 3 \rightarrow22 \\ n = 4 \rightarrow28 \\ n = 5 \rightarrow34 \\ n = 6 \rightarrow40[/tex]
Answer:
∑-2 + 6n
Step-by-step explanation:
4, 10, 16, ......
7 terms
nth term is a + (n - 1)*d
= 4 + (n -1 )*6
= 4 + 6n - 6
= -2 + 6n
so sigma notation would be
∑-2 + 6n
u can also check terms
n = 1 -> -2 + 6 = 4
n = 2 -> -2 + 6*2 = 10
n = 3 -> -2 + 6*3 = 16
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