Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
[tex] \sum_{n = 0}^{6} 4 + 6n \\ n = 0 \rightarrow4\\ n = 1 \rightarrow10 \\ n = 2 \rightarrow16 \\ n = 3 \rightarrow22 \\ n = 4 \rightarrow28 \\ n = 5 \rightarrow34 \\ n = 6 \rightarrow40[/tex]
Answer:
∑-2 + 6n
Step-by-step explanation:
4, 10, 16, ......
7 terms
nth term is a + (n - 1)*d
= 4 + (n -1 )*6
= 4 + 6n - 6
= -2 + 6n
so sigma notation would be
∑-2 + 6n
u can also check terms
n = 1 -> -2 + 6 = 4
n = 2 -> -2 + 6*2 = 10
n = 3 -> -2 + 6*3 = 16
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.