9514 1404 393
Answer:
72 M&Ms
Step-by-step explanation:
We understand the problem to say ...
That 7/12 full condition corresponds to 42 M&Ms being present.
42 = 7/12·full
full = 42(12/7) = 72
There were 72 M&Ms in the jar on Monday evening.
_____
Check
1/8 of 72 = 9 were eaten Tuesday
1/3 of the remaining 63 disappeared on Wednesday. That number is 21, so 63-21 = 42 remained after Wednesday. That is the number seen early Thursday.
There were 72 M & M's in the jar on Monday evening
Let the initial number be x.
When 1/8 of the M & M were eaten on Tuesday, the remaining proportion is:
Remaining = (1 - 1/8) * x
This gives
Remaining = 7x/8
When 1/3 of the M & M disappeared on Wednesday, the remaining proportion is:
Remaining = (1 - 1/3) * 7x/8
This gives
Remaining = 7x/12
On Thursday, the remaining number of M & M is 42.
This means that:
7x/12 = 42
Divide both sides by 7
x/12 = 6
Multiply both sides by 6
x = 72
Hence, there were 72 M & M's in the jar on Monday evening
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