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Monday evening, the jar of M & M's© is full. Tuesday, 1 8 of the M & M's are eaten. Wednesday, 1 3 of the M & M's that remained disappeared. Thursday morning, first thing, the jar had 42 M & M's remaining. How many M & M's were in the jar on Monday evening? M & M's

Sagot :

sqdancefan

9514 1404 393

Answer:

  72 M&Ms

Step-by-step explanation:

We understand the problem to say ...

  • Monday the jar was full
  • Tuesday the jar was 7/8 full (1/8 gone)
  • Wednesday, the jar was (7/8)(2/3) = 7/12 full

That 7/12 full condition corresponds to 42 M&Ms being present.

  42 = 7/12·full

  full = 42(12/7) = 72

There were 72 M&Ms in the jar on Monday evening.

_____

Check

1/8 of 72 = 9 were eaten Tuesday

1/3 of the remaining 63 disappeared on Wednesday. That number is 21, so 63-21 = 42 remained after Wednesday. That is the number seen early Thursday.

MrRoyal

There were 72 M & M's in the jar on Monday evening

How to determine the number of M & M's?

Let the initial number be x.

When 1/8 of the M & M were eaten on Tuesday, the remaining proportion is:

Remaining = (1 - 1/8) * x

This gives

Remaining = 7x/8

When 1/3 of the M & M disappeared on Wednesday, the remaining proportion is:

Remaining = (1 - 1/3) * 7x/8

This gives

Remaining = 7x/12

On Thursday, the remaining number of M & M is 42.

This means that:

7x/12 = 42

Divide both sides by 7

x/12 = 6

Multiply both sides by 6

x = 72

Hence, there were 72 M & M's in the jar on Monday evening

Read more about proportion at:

https://brainly.com/question/1781657

#SPJ9

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