By using the concept of work and energy, the below are the answers
1. 100J
2. 100J
3. 0
4. Total energy = K.E + P.E
5. 1.02 kg
6. 14 m/s
Given that 100 J of work was done to lift a 10-N rock and set it at Position A near the edge of a cliff.
1. If the 100 Joules of work lifted the rock to the top of the cliff, how much potential energy did the rock gain?
Work is the product of force and the distance.
The potential energy gained by the rock will be equal to work done in lifting up the rock which is 100 J
2. At point C, the rock's potential energy will be equal to the work done.
That is, at point C, P.E = 100J
3. The rock's kinetic energy at point A is Zero.
That is, at point A, K.E = 0
4. At point B, some of the rock's potential energy will be changed to Kinetic energy. Yes. Because the Total energy = K.E + P.E
5. What is the mass of the rock?
Weight W = mg
where g = 9.8m/s^2
W = 10N
Substitute both into the formula
10 = 9.8m
make m the subject of the formula
m = 10/9.8
m = 1.02 kg
6. What is the rock's velocity just before it hits the ground
Work done = Energy
That is, Work done = maximum P.E = maximum K.E
100 = 1/2m[tex]v^{2}[/tex]
Substitute mass into the formula
200 = 1.02[tex]V^{2}[/tex]
V = [tex]\sqrt{196}[/tex]
V = 14 m/s
Learn more here: https://brainly.com/question/23503524
