Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Put these in order starting with the smallest.

Put These In Order Starting With The Smallest class=

Sagot :

xenia168

Answer:

Step-by-step explanation:

[tex]9^{\frac{3}{2} }[/tex] = ( √9 )³ = 27

[tex]27^{\frac{1}{3} }[/tex] = ∛27 = 3

[tex]125^{\frac{2}{3} }[/tex] = ( ∛125 )² = 25

[tex]27^{\frac{1}{3} }[/tex] , [tex]125^{\frac{2}{3} }[/tex] , [tex]9^{\frac{3}{2} }[/tex]

watsonultra2

Answer:

[tex] {27}^{ \frac{1}{3} } < {125} ^{ \frac{2}{3} } < {9}^{ \frac{3}{2} }[/tex]

Step-by-step explanation:

[tex] {9}^{ \frac{3}{2} } = \sqrt[2]{ {9}^{3} } = \sqrt[2]{ {3}^{6} } = { 3}^{3} \\ {27}^{ \frac{1}{3} } = \sqrt[3]{27} = \sqrt[ 3]{ {3}^{3} } = 3 \\ {9}^{ \frac{3}{2} } > {27}^{ \frac{1}{ 3} } \\ \\ {125}^{ \frac{2}{3} } = \sqrt[3]{ {125}^{2} } = \sqrt[3]{ {5}^{6} } = 25 \\ \\ 3 < 25 < {3}^{3} \\ {27}^{ \frac{1}{3} } < {125} ^{ \frac{2}{3} } < {9}^{ \frac{3}{2} }[/tex]

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.