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Sagot :
[tex]A)\\\begin{array}{ccc}2\ lb&-&\$3.00\\\\x\ lb&-&\$9.00\end{array}\ \ \ |cross\ multiply\\\\3x=2\cdot9\\3x=18\ \ \ \ |divide\ both\ sides\ by\ 3\\\boxed{x=6\ (lb)}[/tex]
[tex]B)\\1\ oz=\frac{1}{16}\ lb\to5\ oz=\frac{5}{16}\ lb\\\\weight\ of\ 24\ apples:24\cdot\frac{5}{16}\ lb=7.5\ lb\\\\2\ lb\ cost\ \$3.00\to1\ lb\ cost\ \$1.50\\\\7.5\ lb\ cost\ 7.5\cdot\$1.5=\$11.25 > \$9\\\\Answer:\boxed{NO}[/tex]
[tex]B)\\1\ oz=\frac{1}{16}\ lb\to5\ oz=\frac{5}{16}\ lb\\\\weight\ of\ 24\ apples:24\cdot\frac{5}{16}\ lb=7.5\ lb\\\\2\ lb\ cost\ \$3.00\to1\ lb\ cost\ \$1.50\\\\7.5\ lb\ cost\ 7.5\cdot\$1.5=\$11.25 > \$9\\\\Answer:\boxed{NO}[/tex]
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