Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Have you heard the expressions "shooting fish in a barrel" or
"taking candy from a baby" ?
I've decided to take your points and try not to feel guilty about it.
A). That's it ! That's the equation, for ANY basketball on Earth.
You wrote it right there in your question.
In that equation that you wrote, the ' r ' is the initial velocity.
You said that Adam tossed it straight up, and it was going 10 meters per second
when it left his hand.
So ' r ' in the equation is +10.
The equation is:
d = 10t - 5t² .
It tells you how high the ball is above its tossing height after any number of seconds.
The ' t ' in the equation is the number of seconds. Any letter could have been used,
but ' t ' was cleverly selected because it stands for 'time'.
B). You want to know where it is after 0.5 second ? All you have to do is put '0.5'
into the equation wherever there's a ' t '. Do you really need somebody to do that
for you ?
Well, OK. You're being so overly generous with your points . . .
Distance = 10 t - 5 t²
Distance = 10 (0.5) - 5 (0.5)²
Distance = 5 - 5(0.25)
Distance = 5 - 1.25
Distance = 3.75 meters
positive 3.75 means above Adam's hand.
A thinking exercise:
-- He tossed the ball upwards at 10 meters per second.
-- Why is it not 5 meters above his hands after 0.5 second?
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.