Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
75 km/hr, so in other words 75 km per hour.
7200 s / 60 = 120 min
120 min / 60 =2 hr
so 150 km / 2 hr = 75 km per hour
7200 s / 60 = 120 min
120 min / 60 =2 hr
so 150 km / 2 hr = 75 km per hour
Answer:
The speed of the car is [tex]\boxed{75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}}[/tex] or [tex]\boxed{20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}}[/tex] .
Further Explanation:
Given:
The distance covered by the car is [tex]150\,{\text{km}}[/tex].
The time taken by the car to cover the distance is [tex]7200\,{\text{s}}[/tex] .
Concept:
The speed of a car is the ratio of the distance covered by the car to the time taken by the car in covering the distance.
The expression for the speed of the car is:
[tex]v = \dfrac{d}{t}[/tex] …… (1)
Here, [tex]v[/tex] is the speed of the car, [tex]d[/tex] is the distance covered and [tex]t[/tex] is the time taken by the car.
Substitute the value of distance and time in the above expression.
[tex]\begin{aligned}v &= \frac{{150\,{\text{km}}}}{{7200\,{\text{s}}\left( {\frac{{1\,{\text{hr}}}}{{60 \times 60\,{\text{s}}}}} \right)}}\\&= \frac{{150}}{2}\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\\&= 75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\\\end{aligned}[/tex]
The speed of the car in terms of [tex]{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}[/tex] can be expressed as.
[tex]\begin{aligned}v&=75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}}{{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}\left( {\frac{{1000\,{\text{m}}}}{{3600\,{\text{s}}}}} \right)\\&=75 \times\frac{5}{{18}}\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\&= 20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace} {\text{s}}}\\\end{aligned}[/tex]
Thus, the speed of the car is [tex]\boxed{75\,{{{\text{km}}} \mathord{\left/{\vphantom {{{\text{km}}} {{\text{hr}}}}} \right.\kern-\nulldelimiterspace} {{\text{hr}}}}}[/tex] or [tex]\boxed{20.83\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}}\right.\kern-\nulldelimiterspace} {\text{s}}}}[/tex].
Learn More:
- A test car travels in a straight line along the x axis, the graph in the figure shows https://brainly.com/question/10772739
- A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. What is the average power delivered by the https://brainly.com/question/7956557
- If no friction acts on a diver during a dive, then which of the following statements is true https://brainly.com/question/4633609
Answer Details:
Grade:Middle School
Chapter:Speed and distance
Subject:Physics
Keywords: Speed, velocity, distance, time, distance of 150 km, in 7200 s, speed of the car, ratio of distance, rate of change of distance.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
