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solve for x 9^(x+2)=1/27^(x+12)

Sagot :

thisisbenmanley
[tex]9^{(x+2)}= (1/27)^{(x+12)}\1/27 = 9^{-3/2}\9^{(x+2)}=9^{(-3/2)(x+12)}\x+2=(-3/2)(x+12)\x+2=(-3/2)x-18\(5/2)x=-20\x=-8[/tex]
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