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Sagot :
Probability of [tex]1[/tex] success as per given condition is equals to [tex]0.384475[/tex] ≈ [tex]0.4[/tex].
What is probability?
" Probability is defined as the ratio of number of favourable outcomes to the total number of outcomes.Probability is always less than or equals to one."
Formula used
For binomial experiment
Probability = [tex]^n C_r p^{r} q^{n-r}[/tex]
[tex]p =[/tex]success rate
[tex]q=[/tex] failure rate
[tex]p+q=1[/tex]
[tex]n=[/tex]Number of trials
[tex]r=[/tex] number of success
According to the question,
Total number of trials [tex]'n' =4[/tex]
Number of success [tex]'r' =1[/tex]
[tex]p = 0.35\\\\q = 1-0.35\\ \\\implies q = 0.65[/tex]
Substitute the value to get the required probability,
Probability [tex]= ^4C_1 (0.35)^{1}(0.65)^{4-1}[/tex]
[tex]=\frac{4!}{(4-1)!1!} \times\frac{35}{100}\times(\frac{65}{100})^{3} \\\\= 4 \times \frac{35}{100}\times \frac{274625}{1000000} \\\\= 0.384475[/tex]
≈ [tex]0.4[/tex]
Hence, probability of [tex]1[/tex] success as per given condition is equals to [tex]0.384475[/tex] ≈ [tex]0.4[/tex].
Learn more about probability here
brainly.com/question/11234923
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