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Sagot :
The increase in temperature of the metal hammer is 0.028 ⁰C.
The given parameters:
- mass of the metal hammer, m = 1.0 kg
- speed of the hammer, v = 5.0 m/s
- specific heat capacity of iron, 450 J/kg⁰C
The increase in temperature of the metal hammer is calculated as follows;
[tex]Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}[/tex]
where;
c is the specific heat capacity of the metal hammer
Assuming the metal hammer is iron, c = 450 J/kg⁰C
[tex]\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C[/tex]
Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.
Learn more about heat capacity here: https://brainly.com/question/16559442
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