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If i initially have a gas with a pressure of 84 kpa and a temperature of 350 c and i heat it an additional 230 degrees, what will the new pressure be? assume the volume of the container is constant.

Sagot :

Answer:

67.824

Explanation:  You want to use the combined gas law equation (P1*V1)/(n1*T1)=(P2*V2)/(n2*T2). So first cross out what remains constant, so volume(V) and I assume moles (since it was not mentioned as a change). Then you can solve algebraically for the answer!

Hope this helped!

The new pressure will be 139.2 kpa .

What is the combined Gas Law?

According to combined gas law,

[tex]\rm\dfrac{PV}{nT} = R[/tex]

In the Combined Gas Law,if we change either one of the variables the others will also change.

When the moles of the gas is constant , the above equation can be written as ,

[tex]\rm \dfrac{P'V'}{T'}= \dfrac{PV}{T}[/tex]

Given is P = 84kpa , T= 350⁰ C and T' = 350+230=580⁰ C , V=V' , P'=?

So we will substitute the values in the above formula keeping volume constant.

[tex]\rm \dfrac{P'}{T'}= \dfrac{P}{T}[/tex]

[tex]\rm\dfrac{P'}{580}= \dfrac{84}{350}[/tex]

[tex]\rm P' = \dfrac{84\times 580}{350}[/tex]

[tex]\rm P'= 139.2 \;kpa[/tex]

Therefore the new pressure will be 139.2 kpa .

To know more about Combined Gas Law:

https://brainly.com/question/13154969

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