lena3056
Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Help please!! I will mark brainilist and give a lot of points.



This is Pythagorean theorem.


Formula: a^2+b^2=c^2


When I say ^2 I mean to the power of 2.


The question is asking me to solve for a.


Then give me b and c which is b = 17 1/3 and c = 16.


How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?


Unless I’m wrong.



Please help my solve this!!!!! :D

Sagot :

Answer:

a = 23.588

Step-by-step explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

Hello there,

  • I just looked into the question and you are absolutely right whatever you inferred.
  • I think the question might be wrong.
  • The value of c should be greater than b.
  • I guess it will like this:
  • [tex]b = 16 \: \: \: c = 17 \frac{1}{3} [/tex]
  • The values should be like this.
  • I am solving the equation by this:
  • [tex] {a}^{2} = {c}^{2} - {b}^{2} \\ = > {a}^{2} = {(17 \frac{1}{3}) }^{2} - {(16)}^{2} \\ = > {a}^{2} = {( \frac{52}{3} )}^{2} - {(16)}^{2} \\ = > {a}^{2} = ( \frac{52}{3} - 16)( \frac{52}{3} + 16) \\ = > {a}^{2} = ( \frac{52 - 48}{3} )( \frac{52 + 48}{3} ) \\ = > {a}^{2} = \frac{4}{3} \times \frac{100}{3} \\ = > {a}^{2} = \frac{400}{9} \\ = > a = \sqrt{ \frac{400}{9} } \\ = > a = \frac{20}{3} \\ = > a = 6 \frac{2}{3} [/tex]
  • So, the value of a is
  • [tex]a = 6 \frac{2}{3} [/tex]

Hope you could get an idea from it.

Doubt clarification - use comment section.

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.