lena3056
Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Help please!! I will mark brainilist and give a lot of points.



This is Pythagorean theorem.


Formula: a^2+b^2=c^2


When I say ^2 I mean to the power of 2.


The question is asking me to solve for a.


Then give me b and c which is b = 17 1/3 and c = 16.


How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?


Unless I’m wrong.



Please help my solve this!!!!! :D

Sagot :

Answer:

a = 23.588

Step-by-step explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

Hello there,

  • I just looked into the question and you are absolutely right whatever you inferred.
  • I think the question might be wrong.
  • The value of c should be greater than b.
  • I guess it will like this:
  • [tex]b = 16 \: \: \: c = 17 \frac{1}{3} [/tex]
  • The values should be like this.
  • I am solving the equation by this:
  • [tex] {a}^{2} = {c}^{2} - {b}^{2} \\ = > {a}^{2} = {(17 \frac{1}{3}) }^{2} - {(16)}^{2} \\ = > {a}^{2} = {( \frac{52}{3} )}^{2} - {(16)}^{2} \\ = > {a}^{2} = ( \frac{52}{3} - 16)( \frac{52}{3} + 16) \\ = > {a}^{2} = ( \frac{52 - 48}{3} )( \frac{52 + 48}{3} ) \\ = > {a}^{2} = \frac{4}{3} \times \frac{100}{3} \\ = > {a}^{2} = \frac{400}{9} \\ = > a = \sqrt{ \frac{400}{9} } \\ = > a = \frac{20}{3} \\ = > a = 6 \frac{2}{3} [/tex]
  • So, the value of a is
  • [tex]a = 6 \frac{2}{3} [/tex]

Hope you could get an idea from it.

Doubt clarification - use comment section.

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.