Hello there,
- I just looked into the question and you are absolutely right whatever you inferred.
- I think the question might be wrong.
- The value of c should be greater than b.
- I guess it will like this:
- [tex]b = 16 \: \: \: c = 17 \frac{1}{3} [/tex]
- The values should be like this.
- I am solving the equation by this:
- [tex] {a}^{2} = {c}^{2} - {b}^{2} \\ = > {a}^{2} = {(17 \frac{1}{3}) }^{2} - {(16)}^{2} \\ = > {a}^{2} = {( \frac{52}{3} )}^{2} - {(16)}^{2} \\ = > {a}^{2} = ( \frac{52}{3} - 16)( \frac{52}{3} + 16) \\ = > {a}^{2} = ( \frac{52 - 48}{3} )( \frac{52 + 48}{3} ) \\ = > {a}^{2} = \frac{4}{3} \times \frac{100}{3} \\ = > {a}^{2} = \frac{400}{9} \\ = > a = \sqrt{ \frac{400}{9} } \\ = > a = \frac{20}{3} \\ = > a = 6 \frac{2}{3} [/tex]
- So, the value of a is
- [tex]a = 6 \frac{2}{3} [/tex]
Hope you could get an idea from it.
Doubt clarification - use comment section.
