Answered

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Which quadratic equation has roots-8 + 3i and -8 - 3i?
A x^2 - 16x + 73 = 0
B x^2 - 16x + 79 = 0
C x^2 + 16x + 79 = 0
D x^2 + 16x + 73 = 0

Sagot :

loneguy

The two roots are

[tex]\alpha = -8+3i,~~~ \beta = -8-3i\\\\\\x^2 - (\alpha + \beta)x + \alpha \beta = 0\\\\\implies x^2 - (-8+3i-8-3i)x + (-8+3i)(-8-3i)=0\\\\\implies x^2 +16x + (-8)^2+3^2 =0\\\\\implies x^2 +16x +64+9=0\\\\\implies x^2 +16x +73[/tex]

Hence the answer is D.

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