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8. Twice the greatest of three consecutive integers is 10 more that the smallest integer. Find the 3 integers.

Sagot :

mathstudent55

Answer:

6, 7, 8

Step-by-step explanation:

Let the smallest integer be x.

The next greater one is x + 1.

The greatest of the three is x + 2.

Now we use the sentence "Twice the greatest of three consecutive integers is 10 more that the smallest integer." to write an equation.

2(x + 2) = x + 10

Solve the equation for x to find the smallest of the integers.

2x + 4 = x + 10

x = 6

The next one is x + 1.

x + 1 = 7

The greatest is x + 2.

x + 2 = 8

Answer: 6, 7, 8

Answer:

6, 7, 8

Step-by-step explanation:

You can set up variables to represent each of these integers.

For example: x, x+1, and x+2. Next find out what x is by using what the question has told you.

Since twice the greatest of three consecutive integers is 10 more than the smallest integer, you can set up this equation: (x) + 10 = 2(x + 2). x represents the smallest integer while x + 2 represents the greatest integer.

Next solve for x using PEMDAS.

1. (x) + 10 = 2(x + 2)

2. x + 10 = 2x + 4

3. 2x - x = 10 - 4

4. x = 6

Now you can find the other integers by adding 1 and 2 to 6.

The correct answers should be 6, 7, 8.

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