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Sagot :
[tex]T =\dfrac 5{V+1}\\\\\\\implies VT+T = 5\\\\\implies VT = 5-T\\\\\implies V =\dfrac{5-T}T[/tex]
Answer: [tex]V = \frac{5}{T} - 1[/tex] OR [tex]V = \frac{5 - T}{T}[/tex]
Step-by-step explanation:
One way we can make V the subject of the formulas by rearranging the terms mathematically to get V on one side of the equation and the other terms on the other side:
since T = 5 ÷ (V + 1) [multiply both sides by (V+1)]
T (V + 1) = 5 [divide both sides by T]
(V + 1) = 5 ÷ T [subtract 1 from both sides]
V = (5 ÷ T) - 1 OR [tex]V = \frac{5}{T} - 1[/tex]
If we want the RHS with over a single denominator we can write it as
V = (5 ÷ T) - (T ÷ T) [rewrite 1 in terms of T (T/T)]
V = (5 - T) ÷ T OR [tex]V = \frac{5 - T}{T}[/tex]
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