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Sagot :
We must write and solve a system of equations to see how many of each type of coin Carlos has.
The answer is:
- There are 19 pennies.
- There are 19 dimes.
- There are 8 quarters.
We start by defining the variables:
- x = number of pennies in the box.
- y = number of dimes in the box.
- z = number of quarters in the box.
We know there are 46 coins in total, thus:
x + y + z= 46
The number of pennies and dimes is the same, thus:
x = y
The total value of the coins in the box is $4.09, then:
x*$0.01 + y*$0.10 + z*$0.25 = $4.09
So we can write the system of equations:
x + y + z= 46
x = y
x*$0.01 + y*$0.10 + z*$0.25 = $4.09
First, we can replace x by y in the first and third equations (by using the second one) to get:
2y + z = 46
y*$0.11 + z*$0.25 = $4.09
Now we can isolate z in the first equation to get:
z = 46 - 2y
And replace that in the other equation:
y*$0.11 + (46 - 2y)*$0.25 = $4.09
Now we can solve the equation for y:
y*$0.11 + (46 - 2y)*$0.25 = $4.09
y*$0.11 + $11.50 - y*$0.50 = $4.09
y*($0.11 - $0.50) = $4.09 - $11.50
y*(-$0.39) = -$7.41
y = (-$7.41)/(-$0.39) = 19
if y = 19, then x = 19
By using the first equation:
x + y + z = 46
19 + 19 + z = 46
z = 46 - 19 - 19 = 8
We can conclude that:
- There are 19 pennies.
- There are 19 dimes.
- There are 8 quarters.
If you want to learn more about systems of equations, you can read:
https://brainly.com/question/13997560
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