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Answer:
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Step-by-step explanation:
a1 = first term; an= an-1 + d a1 = the first term in the sequence an = the nth term in the sequence an-1 = the term before the nth term n = the term number d = the common difference.
{10, 15, 20, 25, 30, 35, } first term = 10, common difference = 5 recursive formula: a1= 10; an= an-1 + 5
f(n) = f(n-1) + 12
f(1) = 7
f(2) = (7-1) + 12 = 18
f(3) = (18-1) + 12 = 29
f(4) = (29-1) + 12 = 40
f(5) = (40-1) + 12 = 51
7, 18, 29, 40, 51
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