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need help with pre-cal please

Need Help With Precal Please class=

Sagot :

mhanifa

Answer:

  • x = n² ± n√(n² + 8)

Step-by-step explanation:

  • x ≠ 0, n ≠ 0
  • 4/x² + 1/x = 1/(2n²)
  • (x + 4)/x² = 1/(2n²)
  • 2n²(x + 4) = x²
  • x² - 2n²x - 8n² = 0
  • D = (-2n²)² - 4(-8n²) = 4n⁴ + 32n² = 4n²(n² + 8)
  • x = (2n² ± 2n√(n² + 8))/2
  • x = n² ± n√(n² + 8)
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