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The sum of the squares of two numbers is 202 the difference of the numbers is -2 both numbers are positive find the numbers

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viginiengum

Answer: a2 + b2 = 202

Step-by-step explanation: Since they are consecutive odd integers, then we can just divide 202 by 2, square root it, then round to the nearest two odd integers. In this case, 202 / 2 = 101 ⇒ 1010.5 ≈ 10.04. The two nearest odd integers are 9 and 11. We can verify that this is the pair: 92 + 112 = 81 + 121 = 202.

Answer:

[tex]\left \{ {x-y=-2\atop {x^2+y^2=202[/tex]  ⇔  [tex]\left \{ {{y=11} \atop {x=9}} \right.[/tex]

Step-by-step explanation:

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