Answer:
Your answer is below …….
Explanation:
25. Brutus, a champion weightlifter, raises
240 kg of weights a distance of 2.35 m.
a. How much work is done by Brutus
lifting the weights?
W=Fd=mgd
= (240 kg)(9.80 m/s2)(2.35 m)
= 5.5 x 103j
b. How much work is done by Brutus
holding the weights above his head?
d=0, so no work
c. How much work is done by Brutus
lowering them back to the ground?
d is opposite of motion in part a, so
W is also the opposite, -5.5 x 103 J.
d. Does Brutus do work if he lets go of
the weights and they fall back to the
ground?
No. He exerts no force, so he does
no work, positive or negative.
If Brutus completes the lift in 2.5 s.
how much power is developed?
* = multiply
[tex]P = \frac{W}{t} = \frac{5.53 * 10x^{3} J}{2.5s} = 2.2 kW[/tex]
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(Hope this helps can I pls have brainlist (crown)☺️)
