Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The largest angle for which box B will not slip is 16.7⁰.
The given parameters:
- weight of box, W = 10 lb
- coefficient of static friction between box A and box B, [tex]\mu_s_1[/tex] = 0.24
- coefficient of static friction between box B and the inclined surface, [tex]\mu_s_2[/tex] = 0.3
The frictional force between box A and box B is calculated as;
[tex]F_f_1= \mu_s_1 (mg)[/tex]
The frictional force between box B and inclined surface is calculated as;
[tex]F_f = \mu_s_2 (2mg) cos(\theta)[/tex]
The net force on the boxes that results in no movement is calculated as;
[tex](2mg) sin(\theta) - F_f= 0\\\\(2mg) sin(\theta) = F_f\\\\(2mg) sin(\theta) = \ \mu_s_2 (2mg) cos(\theta)\\\\ sin(\theta) = \mu_s_2 cos(\theta)\\\\\mu_s_2 = \frac{sin(\theta)}{cos(\theta)} \\\\\mu_s_2 = tan(\theta)\\\\\theta = tan^{-1} (\mu_s_2)\\\\\theta = tan^{-1} (0.3)\\\\\theta = 16.7 \ ^ 0[/tex]
Thus, the largest angle for which box B will not slip is 16.7⁰.
Learn more about coefficient of static friction here: https://brainly.com/question/25050131
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.