Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

QUESTION 2

What is the pressure in atm of 0.742 mole of gas at 10.91 L and 291 K?

I

Sagot :

Lanuel

The pressure of this gas in atm is equal to 1.63 atm.

Given the following data:

  • Number of moles = 0.742 mole
  • Volume = 10.91 Liters
  • Temperature = 291 K
  • Ideal gas constant, R = 0.0821 Latm/molK

To calculate the pressure of this gas, we would use the ideal gas law equation;

[tex]P=\frac{nRT}{V}[/tex]

Where;

  • P is the pressure.
  • V is the volume.
  • n is the number of moles of a gas.
  • R is the ideal gas constant.
  • T is the temperature.

Substituting the given parameters into the formula, we have;

[tex]P=\frac{0.742 \times 0.0821 \times 291}{10.91} \\\\P = \frac{17.73}{10.91}[/tex]

Pressure, P = 1.63 atm.

Read more: https://brainly.com/question/25706436

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.