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Sagot :
Answer:
cm^3 —> dm^3
divide by 1000
159.5 — Mr of CuSO4
n (moles in mol) = c (concentration in mol/dm^3) * v (volume in dm^3)
0.100 mol of CuSO4 dissolved in 0.5dm^3 of water
calculate for mass of CuSO4 dissolved in 0.03dm^3 (30cm^3) of the solution
n = m/Mr
m = n*Mr
if 0.1 mol is dissolved in 0.5 dm^3 of water
0.5/0.03 ≈ 16.66666667
0.1 = 0.05
0.1 / 16.66666667 = 0.006
0.5 / 16.66666667 = 0.03
0.006 (mol of CuSO4) = 0.03 (dm^3 solution)
0.006 * 159.5 = 0.957 g
I think this is the answer
The mass copper sulphate CuSO₄ in 30ml solution is 957.6g.
How to determine the mass of copper sulphate in the given solution?
To determine the mass of copper sulphate in the given solution, compare both the molarity given
M₁V₁=M₂V₂
n₁/V1=n₂/V2
0.1/0.5=n₂/30 cm³=ml
n₂=6 moles
6×159.5=957.6g
Multiply the calculated moles with the relative mass/molecular mass to get the mass of CuSO₄.
hence, the mass of CuSO₄ is 957.6g
Learn more about dilution equation.
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