Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
cm^3 —> dm^3
divide by 1000
159.5 — Mr of CuSO4
n (moles in mol) = c (concentration in mol/dm^3) * v (volume in dm^3)
0.100 mol of CuSO4 dissolved in 0.5dm^3 of water
calculate for mass of CuSO4 dissolved in 0.03dm^3 (30cm^3) of the solution
n = m/Mr
m = n*Mr
if 0.1 mol is dissolved in 0.5 dm^3 of water
0.5/0.03 ≈ 16.66666667
0.1 = 0.05
0.1 / 16.66666667 = 0.006
0.5 / 16.66666667 = 0.03
0.006 (mol of CuSO4) = 0.03 (dm^3 solution)
0.006 * 159.5 = 0.957 g
I think this is the answer
The mass copper sulphate CuSO₄ in 30ml solution is 957.6g.
How to determine the mass of copper sulphate in the given solution?
To determine the mass of copper sulphate in the given solution, compare both the molarity given
M₁V₁=M₂V₂
n₁/V1=n₂/V2
0.1/0.5=n₂/30 cm³=ml
n₂=6 moles
6×159.5=957.6g
Multiply the calculated moles with the relative mass/molecular mass to get the mass of CuSO₄.
hence, the mass of CuSO₄ is 957.6g
Learn more about dilution equation.
https://brainly.com/question/11493179
#SPJ2
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
