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Sagot :
Answer:
5.96 g/cm^3
Explanation:
Corner atom = 1/8
Atoms in center = 1
Atoms in face of the cube= 1/2
Molar mass of V = 50.94 g/mol (from period table)
1 mole = 6.02x10^23
In BCC unit cell:
(8 x 1/8)+ 1=2 per 1 unit cell
Mass: 2(50.94g)/6.02x10^23 = 1.69x10^-22 g/unit cell
305pm=(305x10^-12m÷10^-2m) x (1mL÷1cm^3)
= 2.837 x 10^-23 mL
1pm=10^-12m
1cm=10^-2m
1mL=1cm^3
density=mass/volume
density of V = 1.69x10^-22g÷2.837x10^-23mL
=5.957g/mL
=5.96g/cm^3
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